8300=4.9(t^2)

Solution for 8300=4.9(t^2) equation:

8300=4.9(t^2)

We move all terms to the left:

8300-(4.9(t^2))=0

We get rid of parentheses

-4.9t^2+8300=0

a = -4.9; b = 0; c = +8300;
Δ = b2-4ac
Δ = 02-4·(-4.9)·8300
Δ = 162680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{162680}=\sqrt{196*830}=\sqrt{196}*\sqrt{830}=14\sqrt{830}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{830}}{2*-4.9}=\frac{0-14\sqrt{830}}{-9.8}
=-\frac{14\sqrt{830}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{830}}{2*-4.9}=\frac{0+14\sqrt{830}}{-9.8}
=\frac{14\sqrt{830}}{-9.8}
$